St. John Paul II served as head of the Catholic Church and sovereign of Vatican City from 16 October 1978, until his death on 2 April 2005.
John Paul II was born on 18 May 1920 in Wadowice, Poland and if he were still alive, he would have turned 100 years old on 18 May 2020.
I constructed the following birthday curiosities in his honor:
St. John Paul II died on the 92nd day of 2005, 46 days before his 85th birthday. Interestingly, 92 is double 46.
Also, the reverse of 85, namely 58, equals twice 29, and the reverse of 29 is 92.
Furthermore, the sum of the squares of the digits of 92 yields 85.
Number 92 constitutes the middle two digits of 1920, the birth year of John Paul II.
Moreover, 92 equals four times the sum of 18 and 5, the day and month numbers of the birthdate of John Paul II.
John Paul II became Pope on 16 October 1978 and if 16/10/1978 is split in the middle into 1610 and 1978, the difference of these two numbers equals four times 92.
Additionally, the product of the digits of 92 yields 9×2=18, the day number of his birthday. Also, the sum of the digits of 92 gives 9+2=11, 11 is the 5th prime number, and 5 is the month number of his birthday.
Pope John Paul II would have turned 100 on 18/05/2020, 100=4×25, 4+25=29, the reverse of 92.
Further, positive square root of 100 is 10, the 10th prime number is 29, and again, the reverse of 29 is 92.
Lastly, if the 100th birthday of John Paul II expressed as 18/05/2020 is split in the middle as 1805 and 2020, these two numbers differ by 215, the reverse of 215 is 512, 512 is 2^9, and 2 and 9 are the digits of 92.
Aziz Inan is a professor teaching in the electrical engineering program of the Donald P. Shiley School of Engineering at the University of Portland and he can be reached at [email protected].
P.S. Last year, I published the following article to celebrate the 99th birthday of Pope John Paul II: